php 链接 mysql

$result = mysql_query("SELECT * FROM Cno");//查找
没有执行成功



mysql_fetch_array() expects parameter 1 to be resource, boolean given in D:\xampp\htdocs\4.php on line 12

请问是什么错误？如何改正？谢谢大家啊~

代码如下：

<?php
$con = mysql_connect("localhost","root ","");
//通过服务器locahost建立连接，用户名为root，无密码

if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }//如果不成功，显示错误
mysql_select_db("crms", $con);//选择数据库
$result = mysql_query("SELECT * FROM Cno");//查找

while($row = mysql_fetch_array($result))//打印
  {
  echo $row['Cno'] . " " . $row['Cno'];
  echo "<br />";
  }

mysql_close($con);
?>