php – 添加prepare语句结果警告

我正在尝试使用prepare语句创建最佳的全局选择查询,除了我收到警告之外,一切正常：

警告：mysqli_stmt_bind_result()：绑定变量数与预准备语句中的字段数不匹配

独特的全局选择功能

function querysp($selectquery, $type_bind, $colval) {    global $db;    $stmt = $db->prepare($selectquery);    $stmt->bind_param($type_bind,$colval);    $stmt->execute();    mysqli_stmt_bind_result($stmt, $colval);    $arr = array();    if ($stmt) {        while ($result = mysqli_stmt_fetch($stmt)) {            array_push($arr, $result);        }    }    return $arr;    }

示例使用：

$select = "SELECT * from advertising WHERE status = ?";$status = 1;$advertising = querysp($select, 'i', $status);foreach ($advertising as $ad) {    $banner[] = $ad['banner'];    $bannercode[] = $ad['bannercode'];    $location[] = $ad['location'];    $status = $ad['status'];}

我错过了什么？很抱歉没有完全准备好staments,也在SO和谷歌检查,但无法解决这个问题.

编辑2

我已经更改了选择查询,因为我将绑定参数的类型从b(我认为这意味着布尔值)更改为i,但仍然收到错误.

编辑3 – 当前版本 – 仍然得到相同的错误：

$select = "SELECT banner, bannercode, location, status from advertising WHERE status = ?";$status = 1;$advertising = querysp($select, 'i', $status);foreach ($advertising as $ad) {    $banner[] = $ad['banner'];    $bannercode[] = $ad['bannercode'];    $location[] = $ad['location'];    $status = $ad['status'];}

和功能

function querysp($selectquery, $type_bind, $colval) {    global $db;    $stmt = $db->prepare($selectquery);    $stmt->bind_param($type_bind,$colval);    $stmt->execute();    $stmt->bind_result($result);    $arr = array();    while($stmt->fetch()) {        $arr[] = $result;    }    $stmt->close();    return $arr;}

解决方法:

花了一些时间,但这里是我准备好的陈述的版本,它是一个相当的墙,但它几乎捕获了可能产生的大多数错误.我试着在这里和那里添加一些文档来解释会发生什么.只需逐步阅读,您就可以理解会发生什么.如果有任何不清楚的地方提问.

要使用下面发布的类,请执行此操作.

$query  = "SELECT ? FROM ?"; // can be any query$params = array($param1, $param2); //must equal to ammount of "?" in query.//an error will occur if $param1 or 2 is not of the type string, int, //bool or double, it can however be a double like this 2,1 instead of 2.1$db = new databaseHandler();$result = $db->runQuery($query, $params);//or for short runQuery("SELECT * FROM *" , array());if($result !== false){    while($row = mysqli_fetch_array($result){        $column1 = $row['columnname'];        //just do with the result what you want.    }}else{    echo "error occured";}

这是能够处理数据库交互的类.不要以你想要的方式设置连接.您可以对此运行所有类型的查询.

class databaseHandler{private $x = ""; //required//$query = the query, $params = array with params can be empty.public function runQuery($query, Array $params){    if($this->checkparams($params, $query)){        //starts and returns the database connection        $con = startConnection();    //<--- CHANGE THIS SO IT WORKS FOR YOU        if($stmt = $con->prepare($query)){            //obtains type of params if there are any.            if(count($params) < 0){                $type = "";                $i=0;                foreach($params as $par){                    $par = $this->checktype($par);                    $params[$i] = $par;                    $type = $this->setType($type);                    if($type === false){                        echo "type error occured"                        return false;                    }                    $i  ;                }                //sets $type on the first spot of the array.                array_unshift($params, $type)                //binds the params                call_user_func_array(array($stmt, 'bind_param'), $this->refValues($params));            }            $stmt->execute();            $result - $stmt->get_result();            stmt->close();            return $result; // return the result of the query.        }else{            echo "error occured, bad connection";            return false;    }else{        echo "params dont match prepared statement";        return false;    }}//checks if params are equal to prepared statement requirements.checkparams($params, $query){    //counts occurences of ? in query.    $count = substr_count($q, "?");    $i = count($params);    if($count == $i){        return true;    }else{        return false;    }}//Checks the type of a parampublic function checktype($par){    $this->x = gettype($par);    if($this->x == "string"){        $npar = str_replace(",", ".", $par);        if(is_numeric($npar)){            $this->x = "integer";            if(strpos($npar, ".")){                $this->x="double";                return $npar;            }        }    }    return $par;}//sets/adds to the type.public function setType($type){    //$this->x from checktype;    switch($this->x){        case "string":        $type = $type."s";        break;        case "integer":        $type = $type."i";        break;        case "double":        $type = $type."d";        break;        case "boolean":        $type = $type."b";        break;        case "NULL":        $type = $type."s";        default:            return false;    }    return $type; }//This function exist to resolve a few version errors in php.//not sure what it does exactly, but it resolved some errors I had in the past.               function refValues($arr){    if(strnatcmp(phpversion(),'5.3') >= 0){        $refs = array();        foreach($arr as $key => $value)            $refs[$key] = &$arr[$key];        return $refs;    }    return $arr;}}}

所以这里发生的是一组执行查询的检查,如果出现任何问题,如果没有出错则返回false,即使结果为空,也会返回查询结果.也有可能不在课堂上完成所有这些,尽管这会使$x全局化.我认为最好修改某些东西,使它们最适合您的应用程序.像错误处理/消息变量名称等

此代码唯一不能保护您的是查询中的错误.

编辑—-我发现这个代码没有防止的东西,插入NULL值.我更改了此代码以防止插入NULL值,它们将作为类型字符串插入.数据库将看到其NULL并将其插入为NULL值.

只是不要尝试插入对象或空值,因为这无论如何都是无用的.

来源：https://www.icode9.com/content-1-426651.html