如果一个字符串中有像逗号或其它符号分隔,你想把它折分成列,如’first field, second field , third field’,
拆成
first field
second field
third field
第一种 用10G开始支持的正则表达式
anbob@ANBOB>SELECT REGEXP_SUBSTR ('first field, second field , third field', '[^,]+', 1,rownum) 2 FROM DUAL 3 CONNECT BY ROWNUM <= 4 LENGTH ('first field, second field , third field') - LENGTH (REPLACE ('first field, second field , third field', ',', ''))+1;REGEXP_SUBSTR('FIRSTFIELD,SECONDFIELD,THIRDFIELD','[^,]+',1,ROWNUM)------------------------------------------------------------------------------first fieldsecond fieldthird field
TIP:
REGEXP_SUBSTR 函数是把那个串以正则不是以,(逗号)开头的截取,第二个参数是取第几组,rownum伪列序号,connect 循环 ,循环次数为串总长度-去除分隔符后=几个分隔符 +1
第二种用type,function
第一,先创建一个Type
CREATE OR REPLACE TYPE type_split IS TABLE OF VARCHAR2 (4000)
第二,创建函数
create or replace function split(p_list varchar2,p_sep varchar2 := ’,’)return type_split pipelinedISl_idx pls_integer;v_list varchar2(50) := p_list;begin loop l_idx := instr(v_list,p_sep); if l_idx = 0 then pipe row(substr(v_list,1,l_idx-1)); v_list := substr(v_list,l_idx+length(p_sep)); else pipe row(v_list); exit; end if; end loop;end split;
第三,调试
select * from table(split(‘aaa,bbb,ccc’,',’));
拆分列字段
anbob@ANBOB>select * from test11; ID NAME-------------------- ---------- 1 a,b,c 2 e,dnbob@ANBOB>with temp0 as (select LEVEL lv from dual CONNECT BY LEVEL <= 100) 2 select id,substr(t.vals,instr(t.vals, ',', 1, tv.lv) + 1, 3 instr(t.vals, ',', 1, tv.lv + 1) -( 4 instr(t.vals, ',', 1, tv.lv) + 1) 5 ) AS name 6 from (select id,',' || name || ',' AS vals, 7 length(name || ',') - nvl(length(REPLACE(name, ',')), 0) AS cnt 8 from test11) t join temp0 tv 9 on tv.lv <= t.cnt order by 1; ID NAME-------------------- ------------------------ 1 a 1 b 1 c 2 d 2 e
扩展 regexp_replace
V字段中每个值中字符串以,分隔,如果不是以9开头那组串加‘00’
anbob@NCME>create table testreg(v varchar2(80));
Table created.
anbob@NCME>insert into testreg values(’911,000,12,31′);
1 row created.
anbob@NCME>insert into testreg values(’11911,554000,312,931′);
1 row created.
anbob@NCME>commit;
Commit complete.
anbob@NCME>select ltrim(regexp_replace(‘,’||v,’([,])’,'\100′),’,') newv,v from testreg;
NEWV V
—————————— ——————————
00911,00000,0012,0031 911,000,12,31
0011911,00554000,00312,00931 11911,554000,312,931
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