Linux中awk抽取包含某字段的整行日志

命令示例：
awk '{if($0~"listAuths") print}' xxx.log
解释说明：抽取xxx.log整个日志文件中，包含“listAuths”的行，打印输出




抽取效果：
[root@SZB-L0005724 applogs]# awk '{if($0~"listAuths") print}' csp_iobs_core_trace.log.2016-04-27 
[INFO ] [2016-04-27 17:40:14] com.pingan.iobs.core.aspect.ControllerAspect -  listAuths finished! cost: 4ms. args : listAuths'args : 
[INFO ] [2016-04-27 17:41:13] com.pingan.iobs.core.aspect.ControllerAspect -  listAuths finished! cost: 5ms. args : listAuths'args : 
[INFO ] [2016-04-27 17:45:14] com.pingan.iobs.core.aspect.ControllerAspect -  listAuths finished! cost: 5ms. args : listAuths'args : 
[INFO ] [2016-04-27 17:50:15] com.pingan.iobs.core.aspect.ControllerAspect -  listAuths finished! cost: 5ms. args : listAuths'args : 
[INFO ] [2016-04-27 17:55:15] com.pingan.iobs.core.aspect.ControllerAspect -  listAuths finished! cost: 5ms. args : listAuths'args : 
[INFO ] [2016-04-27 18:00:16] com.pingan.iobs.core.aspect.ControllerAspect -  listAuths finished! cost: 5ms. args : listAuths'args : 
[INFO ] [2016-04-27 18:05:16] com.pingan.iobs.core.aspect.ControllerAspect -  listAuths finished! cost: 4ms. args : listAuths'args : 






详解：http://www.cnblogs.com/ggjucheng/archive/2013/01/13/2858470.html