2013年08月16日 | 作者：佚名 | 来源：比特网
大家熟知的C库函数printf函数就是一个可变参数函数，它是怎么实现的呢?不过他实现是有条件的，必须函数参数的入栈顺序为从右向左的顺序，也即函数的形参，在函数调用之前，必须是最右边的参数先入栈，并且参数都必须通过栈传递，以1个例子说明，如函数func(arg1, arg2,arg3),那么函数的堆栈应是：
ebp是帧指针寄存器，一般用来存取堆栈，有了堆栈结构，下面我们看看C可变参数的具体实现原理：
#include
enum {
ptChar,
ptInt,
ptFloat,
ptDouble,
};
void printSum(unsigned long paramFormat, ...)
{
/*高16位为可变参数类型，低16位为可变参数个数*/
int paramType = (paramFormat >> 16);
int paramNum = paramFormat & 0xffff;
/*?mFormat = ebp 8,第一个参数的地址*/
unsigned long *pArg = ?mFormat;
/*ebp 0x0c, 第二个参数地址*/
pArg ;
switch(paramType)
{
case ptChar:
{
int sum = 0;
for (int i = 0; i < paramNum; i )
{
char *pValue = (char *)pArg;
sum = *pValue;
pArg ;
}
printf("%d\n", sum);
}
break;
case ptInt:
{
int sum = 0;
for (int i = 0; i < paramNum; i )
{
int *pValue = (int *)pArg;
sum = *pValue;
pArg ;
}
printf("%d\n", sum);
}
break;
case ptFloat:
{
float sum = 0;
/**/
pArg ;
/*浮点参数，堆栈占8个字节，所以指针偏移为8*/
for (int i = 0; i < paramNum; i )
{
float *pValue = (float *)pArg;
sum = *pValue;
pArg ;
pArg ;
}
printf("%f\n", sum);
}
break;
case ptDouble:
{
double sum = 0;
/*双精度浮点参数，堆栈占8个字节，所以指针偏移为8*/
for (int i = 0; i < paramNum; i )
{
double *pValue = (double *)pArg;
sum = *pValue;
pArg ;
pArg ;
}
printf("%f\n", sum);
}
break;
default:
printf("unknowned type!\n");
break;
}
}
void main()
{
unsigned long paramFormat = 3;
char a = 1, b = 2, c = 3;
printSum(paramFormat, a, b, c);
paramFormat = ptInt << 16;
paramFormat = 3;
int ia = 1, ib = 2, ic = 3;
printSum(paramFormat, ia, ib, ic);
paramFormat = ptFloat << 16;
paramFormat = 3;
float fa = 1, fb = 2, fc = 3;
printSum(paramFormat, fa, fb, fc);
paramFormat = ptDouble << 16;
paramFormat = 3;
double da = 1, db = 2, dc = 3;
printSum(paramFormat, da, db, dc);
}
上面这种方法对函数参数的入栈顺序有限制，必须从右向左入栈，这就是为什么pascal调用方式不能实现printf的原因，并且函数形参都要通过栈来传递，这对有些编译器为了优化处理，函数参数通过寄存器来传递，从而不满足要求。鉴于次，本文采用C 的默认形参实现可变参数的方法，没有上面的这些限制，下面是实现代码：
#include
enum {
ptChar,
ptInt,
ptFloat,
ptDouble,
};
void printSum(unsigned long paramType,
void *arg1 = NULL,
void *arg2 = NULL,
void *arg3 = NULL,
void *arg4 = NULL,
void *arg5 = NULL,
void *arg6 = NULL,
void *arg7 = NULL,
void *arg8 = NULL,
void *arg9 = NULL,
void *arg10 = NULL)
{
void *arg[10] = {
arg1,
arg2,
arg3,
arg4,
arg5,
arg6,
arg7,
arg8,
arg9,
arg10,
};
switch(paramType)
{
case ptChar:
{
int sum = 0;
for (int i = 0; i < 10; i )
{
if (arg[i] != NULL)
{
char *pValue = (char *)arg[i];
sum = *pValue;
}
else
break;
}
printf("%d\n", sum);
}
break;
case ptInt:
{
int sum = 0;
for (int i = 0; i < 10; i )
{
if (arg[i] != NULL)
{
int *pValue = (int *)arg[i];
sum = *pValue;
}
else
break;
}
printf("%d\n", sum);
}
break;
case ptFloat:
{
float sum = 0;
for (int i = 0; i < 10; i )
{
if (arg[i] != NULL)
{
float *pValue = (float *)arg[i];
sum = *pValue;
}
else
break;
}
printf("%f\n", sum);
}
break;
case ptDouble:
{
double sum = 0;
for (int i = 0; i < 10; i )
{
if (arg[i] != NULL)
{
double *pValue = (double *)arg[i];
sum = *pValue;
}
else
break;
}
printf("%f\n", sum);
}
break;
default:
printf("unknowned type!\n");
break;
}
}
void main()
{
unsigned long paramType = ptChar;
char a = 1, b = 2, c = 3;
printSum(paramType, &a, &b, &c);
paramType = ptInt;
int ia = 1, ib = 2, ic = 3;
printSum(paramType, &ia, &ib, &ic);
paramType = ptFloat;
float fa = 1, fb = 2, fc = 3;
printSum(paramType, &fa, &fb, &fc);
paramType = ptDouble;
double da = 1, db = 2, dc = 3;
printSum(paramType, &da, &db, &dc);
}
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